Assume a normal distribution with an average return of 7% and a standard deviation of 2%. what is the probability of an actual return of (a) more than 11%; and (b) less than 5%?

0.023 is the probability of an actual return of more than 11%.

0.159 is the probability of an actual return of less than 5%.                                              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7%

Standard Deviation, σ = 2%

We are given that the distribution is a bell shaped distribution that is a normal distribution.

Formula:

a) P(more than 11%)

P(x > 11)

Calculation the value from standard normal z table, we have,  

Thus, 0.023 is the probability of an actual return of more than 11%.

b) P(less than 5%)

P(x < 5)

Calculation the value from standard normal z table, we have,  

Thus, 0.159 is the probability of an actual return of less than 5%.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement