In order to solve the system of equations below, harvey multiplies each equation by a constant to eliminate the x terms.

7 x + 3 y = 5. 2 x + 5 y = negative 11.

what are the resulting equations?
14 x + 6 y = 10. negative 14 x minus 35 y = 77.
14 x + 6 y = 10. negative 14 x + 35 y = 77.
14 x + 6 y = 10. negative 14 x minus 35 y = negative 77.
negative 14 x minus 6 y = 10. 14 x + 35 y = negative 77.

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

Step-by-step explanation:

Let's find out the constants to eliminate the x terms

7 x + 3 y = 5

2 x + 5 y = negative 11

Let's multiply the first equation by 2 and the second one by -7, this way:

2 * (7 x + 3 y = 5)

-7 * (2 x + 5 y = negative 11)

14x + 6y = 10

-14x - 35y = 77

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.