Rewrite the equation 2x + 3y = 6 in slope-intercept form.
y = -2 x + 6
y = - (fraction)x + 2
y = 2 x + 6
3 y = -2 x + 6

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Rearrange 2x + 3y = 6 into this form

Subtract 2x from both sides

3y = - 2x + 6 ( divide all 3 terms by 3 )

y = - x + 2 ← in slope- intercept form

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)