How do i find the mid point in a(-3,13) b(15,7) and c(-3,11)

Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)

Step-by-step explanation:

Given that the points are A(-3,13), B(15,7) and C(-3,11)

To find the mid points :

To find midpoint of AB

Let be the points A(-3,13),B(15,7) respectively

Midpoint of AB

Midpoint of AB=(6,10)

To find midpoint of BC

Let be the points B(15,7),C(-3,11) respectively

Midpoint of BC

Midpoint of BC=(6,9)

To find midpoint of CA

Let be the points C(-3,11),A(-3,13),respectively

Midpoint of CA

Midpoint of CA=(-3,12)

Therefore Midpoint of AB=(6,10) ,Midpoint of BC=(6,9) and Midpoint of CA=(-3,12)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length