If y(x) = -2x2+3 and v(x) = x, what is the range of (jov(x)?
(3.00)
(-60,3)
0 (0o,00)

The answer to your question is (-∞, 3)

Step-by-step explanation:

Data

y(x) = -2x² + 3

v(x) = x

Process

1.- Evaluate y(x) in v(x)

   yov(x) = -2(x)² + 3

   yov(x) = -2x² + 3

2.- Graph the function

In the graph we observe that the posible values of "y" are from (-∞, 3) that is the range.

found it xd it ok yt

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct