F(x)=3x^2+5
g(x)=4x-2
h(x)=x^2-3x+1
find f(x)+g(x)-h(x)
a.7x^2+x+4
b.2x^2+x+2
c.2x^2+7x+2
d.5x^2+4

2x^2 + 7x + 2

Step-by-step explanation:

(3x^2 + 5) + (4x-2) - (x^2 - 3x + 1)

distribute the signs to the equations. subtraction on the last one is a little tricky because it turns all of the signs opposite. all subtraction in these kinds of problems is like this so you might want to watch out for this in the future. (:

distribute the signs to get:

3x^2 + 5 + 4x - 2 - x^2 + 3x - 1

simplify the equation. get all like variables together to get:

2x^2 + 7x + 2

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?