Joe is going to rent a truck for one day. company a has no initial fee but charges 80 cents for every mile driven. company b charges an initial fee of $50 and an additional 60 cents for every mile driven. for what mileage will company a charge more than company b?

Therefore the minimum mileage for which Company A will charge more than Company B is 251 miles.

Step-by-step explanation:

i) let x be the number of miles driven

ii) If Joe rents the truck from Company A the Joe will pay Company A

  = $0.8x

iii) If Joe rents the truck from Company B then Joe will pay Company B

   = $50 + $0.6x

iv) the mileage for which the rents of both companies will be equal is given by

  $0.8x = $50 + 0.6x

Therefore 0.2x = $50

Therefore x = miles.

Therefore the minimum mileage for which Company A will charge more than Company B is 251 miles.

the solution is h=10 because you add 9 to each side of the equation.