If the volume of the crystal ball is about 113 14 cm", the radius of the ball is approximately 3 cm. (use = 7.)
if the vacant space inside the box were filled with spray foam, the approximate volume of foam required would
cm^3.

The volume of required foam is 0.1 cm³  

Step-by-step explanation:

Given as :

The volume of box = v = 113.14 cm³

The radius of the crystal ball = r = 3 cm

Let The volume of required foam = V cm³

According to question

Volume of  crystal ball = × π × radius³                        where π = 3.14

i.e Volume of ball = × π × 3³

Or, Volume of ball = × π × 27

Or, Volume of ball = × 3.14 × 27

Or, Volume of ball = 4 × 3.14 × 9

Or, Volume of ball = 113.04 cm³

Again

∵ volume of crystal ball = v' = 113.04 cm³

So ,  The volume of required foam = volume of box - volume of crystal ball

Or, V =  v - v'

Or, V = 113.14 cm³ -  113.04 cm³

∴   V = 0.1 cm³

So, The volume of required foam = V = 0.1 cm³

Hence, The volume of required foam is 0.1 cm³  . Answer

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: