The sum of 4 consecutive integers is 18

3 , 4 , 5 and 6

Step-by-step explanation:

Let the consecutive integers be ; x , x+1 , x + 2 and x + 3 , then their sum implies :

x + (x + 1 )  + (x + 2 ) + ( x + 3 ) = 18

x + x + 1 + x + 2 + x + 3 = 18

4x + 6 = 18

4x = 18 - 6

4x = 12

x = 3

Therefore , the numbers are

3 , 3 + 1 , 3 + 2 and 3 + 3

which are :

3 , 4 , 5 , 6

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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