Phillip departed from town a with coordinates (1, 6) towards town b with coordinates (7, 6). at the same time bruce headed from town b to town a. what are the coordinates of point c where they will meet if bruce is moving twice as fast as phillip?

(3,6)

Explanation:

Since Bruce is moving twice as fast as Phillip, when they meet, Phillip will have moved x units while Bruce will have moved 2x units.

Thus, the distance from A to B will be split in a 1: 2 ratio.

1. Coordinate x of point  C:

Horizontal distance from A to B: 7 - 1 = 6Divide 6 in three parts (1 + 2 = 3): 6 / 3 = 2Phillip will have moved one part, equal to 2 units from (1,6), thus the x-coordinate will be 1 + 2 = 3 units

2. Coordinate y of point C:

Vertical distance from A to B: 6 - 6 = 0That means that there is not movement in the vertical position (y-coordinate), thus the y-coordinate of the point C will be 6 units.

3. Answer:

The coordinates of point C where they will meet are (3,6).

Step 1: 6x-10=1; step 2: 6x=11