Pls me with this question no. 14 asap. will mark brainliest

Work Shown for part (i)

One base of triangle PQR is QR = 4

If the base is QR, then the height is PL = 5, which is perpendicular to QR.

area of triangle PQR = (1/2)*base*height

area of triangle PQR = (1/2)*QR*PL

area of triangle PQR = (1/2)*4*5

area of triangle PQR = 10

Work Shown for part (ii)

Another base for triangle PQR is PR = 8

Imagine rotating triangle PQR so that PR is completely horizontal and flat.

Note: the diagram implies that MR = 8, but instead it's actually PR = 8

For the base PR, the perpendicular height is QM, which we'll label as x for now

area of triangle PQR = (1/2)*base*height

area of triangle PQR = (1/2)*PR*QM

area of triangle PQR = (1/2)*8*x

area of triangle PQR = 4*x

From part (i), we can set 4x equal to 10 since we know the triangle PQR has area 10 square cm.

4x = 10

4x/4 = 10/4

x = 10/4

x = (5*2)/(2*2)

x = 5/2

x = 2.5

any options?

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it