Acompany produces three combinations of mixed vegetables that sell in 1-kg packages. italian style combines 0.4 kg of zucchini, 0.3 kg of broccoli, and 0.3 kg of carrots. french style combines 0.5 kg of broccoli and 0.5 kg of carrots. oriental style combines 0.2 kg of zucchini, 0.3 kg of broccoli, and 0.5 kg of carrots. the company has a stock of 17 comma 800 kg of zucchini, 28 comma 300 kg of broccoli, and 38 comma 900 kg of carrots. how many packages of each style should it prepare to use up existing supplies?

Italian style = 18,000 packages

French style = 14,000 packages

Oriental style = 53,000 packages

Step-by-step explanation:

See the attached figure to represent the question

let the number of packages of Italian style = x

let the number of packages of French style = y

let the number of packages of Oriental style = z

By using the figure we can make the following equations:

0.4x + 0 * y + 0.2z = 17,800

0.3x + 0.5y + 0.3z = 28,300

0.3x + 0.5y + 0.5z = 38,900

Solving the 3 equations together to find x , y and z

Using the calculator:

x = 18,000 ⇒ Italian style packages

y = 14,000 ⇒ French style packages

z = 53,000 ⇒ Oriental style packages

found it xd it ok yt

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.