where is the point of concurrency of the angle bisectors of a triangle?
a. on the triangle
b. outside the triangle
c. inside the triangle
me

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the answer will be b x² +x-1

step-by-step explanation:

won't that be plagrisim thought?

step-by-step explanation: