In a two-digit number the tens digit is four less than the units digit. seven times the tens digit plus five times the units digit is equal to 56. find the digits.

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Step-by-step explanation:

Let our number be “ xy ”

the tens digit is four less than the units digit means y-4=x

Seven times the tens digit plus five times the units digit is equal to 56 means

7x+5y=56

now we have to solve the system:

y-4=x  (1)

7x+5y=56  (2)

(1) ⇒ y=4+x

Then we substitute y by 4+x into the second equation like this:

7x+5(x+4)=56

⇔ 7x+5(x+4)=56

⇔ 12x+20=56

⇔ x = 3

now using equation (1) we get : y=3+4 = 7

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step-by-step explanation: