Find the value of k so that the point a lies on the line given by equation.

a(2, 2), kx+(k+1)y=2

k = 0

Step-by-step explanation:

Explanation:-

given straight line equation is k x+(k+1)y=2(1)

The point A(2,2) lies on the equation is

substitute x = 2 and y=2

k(2) + (k+1)(2) =2

now simplify 2 k+2 k+2 = 2

subtracting '2' on both sides , we get solution is

4 k +2 -2 = 2-2

4 k =0

k = 0

k = 0

Step-by-step explanation:

kx + (k + 1)y = 2

2k + 2(k + 1) = 2

2k + 2k + 2 = 2

4k + 2 = 2

4k + 2 - 2 = 2 - 2

4k = 0

4k ÷ 4 = 0 ÷ 4

k = 0

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

i dont know sorry

step-by-step explanation: