Taxi fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
(a) which should have the greater probability of falling between $21 & $24;
the mean of a random sample of 10 taxi fares or the amount of a single random taxi fare? why?
(b) which should have a greater probability of being over $24-the mean of 10 randomly selected taxi fares or the amount of a single randomly selected taxi fare? why?

Step-by-step explanation:

Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.

For a random single taxi std deviation is 2.20

But for a sample of size 10, std deviation would be

This would be less than the 2.20

Because std devition is less for sample we get a big z score for the sample than the single.  

As positive values of z increase we find that probability would decrease since normal curve is bell shaped.

So single taxi fare would have higher probability than sample.

B) Here >24.

By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

16 is the absolute value

step-by-step explanation: