Can someone explain for how to do this problems ? [tex]5(x - 10) = [/tex][tex]8(x + 1.5) = [/tex][tex]7(x - 3.4) = [/tex][tex]7(x - rac{ 4}{7} ) = [/tex][tex]6(9 + x) = [/tex][tex]8( rac{3}{4} + x) = [/tex] you!

answer: a no=5x-50b no =8x+12c no =7x-23.8d no= 7x-28/49e no=54+6xf no =24/32+8x...

Mathematics, 25.01.2020 05:31, jjtfeb11

Can someone explain for how to do this problems ?

$5(x - 10) =$
$8(x + 1.5) =$
$7(x - 3.4) =$
$7(x - \frac{ 4}{7} ) =$
$6(9 + x) =$
$8( \frac{3}{4} + x) =$

you!

Answers: 1

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Can someone explain for how to do this problems ?

[tex]5(x - 10) = [/tex]
[tex]8(x...

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Can someone explain for how to do this problems ? you!

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Can someone explain for how to do this problems ?

$5(x - 10) =$
$8(x + 1.5) =$
$7(x - 3.4) =$
$7(x - \frac{ 4}{7} ) =$
$6(9 + x) =$
$8( \frac{3}{4} + x) =$

you!