which of the graphs below correctly solves for x in the equation −x2 − 3x − 1 = −x − 4?

graph of quadratic opening downward and linear sloping up to the right. they intersect at point negative 4, negative 2 and point 0, 2.
graph of quadratic opening upward and linear sloping up to the right. they intersect at point 0, 2 and point 4, 6.
graph of quadratic opening downward and linear sloping up to the left. they intersect at point negative 3, negative 1 and point 1, negative 5.
graph of quadratic opening upward and linear sloping up to the right. they intersect at point 2, 0.

Graph of quadratic opening downward and linear sloping up to the left. They intersect at point negative 3, negative 1 and point 1, negative 5

Step-by-step explanation:

we have

we can separate the expression above into two equations

----> equation A

This is a quadratic equation ( vertical parabola) open downward (the leading coefficient is negative)

----> equation B  

This is a linear equation with negative slope (decreasing function).so linear sloping up to the left

The solution of the original expression are the x-coordinates of the intersection point both graphs

using a graphing tool

The intersection points are (-3,-1) and (1,-5)

see the attached figure

step-by-step explanation:

107 units

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step-by-step explanation: