Asporting goods store manager was selling a ski set for a certain price. the manager offered the markdowns shown below, making the one-day sale price of the ski set. the ski set was 10% off and with an extra 30% off.

The complete question is:

A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown, making the one-day sale price of the ski set $325. Find the original selling price of the ski set. It was marked down 10% and 30%

original price = $ 515.87

Explanation:

1. Data:

a) Final price of the ski set: $ 325

b) First mark down: 10%

c) Second mark down: 30%

d) Original selling price: ?

2. Procedure:

First mark down:

Final price = original price - first mark down - second mark downFirst mark down = 10% × original price = 0.10 × original pricePrice after first mark down = original price - 0.10 × original price = 0.90 × original price

Second mark down:

Second mark down = 30% × price after first mark down = 0.30 × price after first mark down = 0.30 × 0.90 × original pricePrice after second mark down = price after first mark down - second mark downPrice after second mark down = 0.90 × original price - 0.30 × 0.90 × original price = (1 - 0.30) × 0.90 × original price = 0.70 × 0.90 × original price

Final price:

Final price = price after second mark down$ 325 = 0.70 × 0.90 × original price

Simplify and solve for the original price:

$325 = 0.63 × original priceoriginal price = $325/0.63 = $515.87

original price = $ 515.87

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

She will need 5/8 bags for each square yard.