Find the appropriate percentile from a t-distribution for constructing the following confidence interval.
99% t-interval with n = 3.

9.9248

Step-by-step explanation:

We know that the critical t- value for confidence interval is a two-tailed value from the t-distribution table corresponding to degree of freedom (df = n-1 , where n is the sample size) and the significance level () .

The given confidence interval = 99%

⇒ Significance level =

Sample size : n=3

DEgree of freedom : df = n-1 = 2

Then, the  critical t- value for 99% confidence interval will be;

  [From t-distribution table]

Hence, the appropriate percentile from a t-distribution for constructing the 99% confidence interval with n = 3 is 9.9248.

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction