Acardboard box manufacturing company is building boxes with length represented by x+ 1, width by 5- x, and height by x -1. the volume of the box is modeled by the function below v(x) 18 14 10 6 24 x 5 6 2 2 3 -2 -6 over which interval is the volume of the box changing at the fastest average rate? [1,2] a. [1,3.5 b. c. [1,5] r0,3.51 d

a. [1,2]

b. [1,3.5]

c. [1,5]

d. [0,3.5]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

Step-by-step explanation:

Assuming that we have the figure attached for the function. For this case we just need to quantify the slope given by:

For each interval and the greatest slope would be the interval on which the volume of the box is changing at the fastest average rate

a. [1,2]

b. [1,3.5]

c. [1,5]

d. [0,3.5]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

i got 10.28 but that rounds up to 10.3