The ages of 3 brothers are represented by consecutive integers. if the oldest brothers age is decreased by twice the youngest brother age the result is -19. how old is the youngest brother

The youngest brother's age is 21 years.

Step-by-step explanation:

Given:

The ages of 3 brothers are consecutive integers.

If the oldest brothers age is decreased by twice the youngest brother age the result is -19

To find the age of the youngest brother.

Solution:

Let the age of youngest broth be =  years

The ages are consecutive integers.

So, age of the next older brother will be = years

The age of the oldest brother will be = years

The oldest brothers age is decreased by twice the youngest brother age.

The above statement can be represented as:

⇒

Simplifying.

⇒

⇒

The result for the above expression = -19.

So, we have:

Subtracting both sides by 2.

Multiplying both sides by -1.

∴

Thus, the youngest brother's age is 21 years

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.