In this problem, y = c₁eˣ + c₂e⁻ˣ is a two-parameter family of solutions of the second-order de y'' − y = 0. find a solution of the second-order iv p consisting of this differential equation and the given initial conditions. y(-1) = 4, y'(-1) = -4.

will be the solutions.

Step-by-step explanation:

The given equation is

Therefore, for x = -1

------(1)

Now y'(-1) = -4

y'(x) = = -4

= -4 -----(2)

By adding equation (1) and (2)

From equation (1),

By placing the values in the parent equation

y =

y =

answer: what if i dont want to show my work boi.

step-by-step explanation: im watching dbz and eating popcorn leave meh alone

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.