Atotal of $500 was invested, part of it at 7 percent interest and the remainder at 8 percent .if the total yearly interest from both investments amounted to $38 ,how much was invested at 8 percent rate?

Step-by-step explanation:

Given that

Total  investment = $ 500

Let $x be invested at 7% and (500-x ) was invested at 8%

∴ The total interest after 1 year =$

According to problem,

= 38

⇔7x +4000 - 8x = 38×100

⇔ -x = 3800 - 4000

⇔x = $ 200

Therefore $(500-200)= $300 was invested at 8% rate

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

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step-by-step explanation: