Suppose that a fungal disease originates in the middle of an orchard, initially affecting only one tree. the disease spreads out radially at a constant speed of 45 feet per day.
(a) what area will be affected after 2 days?
(b) what area will be affected after 4 days?
(c) what area will be affected after 8 days?
(d) write a formula for the affected area as a function of time, measured in days. use t as your variable for time, in days.

a) 25446.90 ft²

b) 101787.60 ft²

c) 407150.41 ft²

d) 2025πt²

Step-by-step explanation:

Data provided in the question:

Rate of spread radially = 45 feet per day

a) Radius of spread after 2 days

= 45 × 2

= 90 feet

Therefore,

Area affected = πr²

= π(90)²

= 25446.90 ft²

b) Radius of spread after 2 days

= 45 × 4

= 180 feet

Therefore,

Area affected = πr²

= π(180)²

= 101787.60 ft²

c) Radius of spread after 2 days

= 45 × 8

= 360 feet

Therefore,

Area affected = πr²

= π(360)²

= 407150.41 ft²

a) Radius of spread after t days

= 45 × t ft

Therefore,

Area affected = πr²

= π(45t)²

= 2025πt²

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

entering that problem on the tube might get you an answer