Abox contains 15 resistors. ten of them are labeled 50 ω and the other five are labeled 100 ω.

(a) what is the probability that the first resistor is 100ω?
(b) what is the probability that the second resistor is 100 ω, given that the first resistor is 50 ω?
(c) what is the probability that the second resistor is 100 ω, given that the first resistor is 100 ω?

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18