Ahorizontal clothesline is tied between 2 poles, 10 meters apart. when a mass of 2 kilograms is tied to the middle of the clothesline, it sags a distance of 2 meters. what is the magnitude of the tension on the ends of the clothesline?

T = 26.16 [N]

Step-by-step explanation:

We have a mass of 2 kg  and a horizontal clothesline tied between two poles 10 meters apart. middle point is 5 meters apart of any of the two poles

Mass of 2 kg  means P = 2 kg * g       ⇒  P = 2 kg* 9.8 m/sec

P = 19.6 [N]

In a free body diagram is easy to see that we will have a force P = 19.6 [N]  acting downwards and two equals tension acting through each half of the clotheslines.

As the clothesline sags, an angle θ with the horizontal line passing at body level,  such as   tan θ = 2/5    tan θ  =  0.4    then from tables we get

θ = 22 ⁰

sin 22 ⁰  =  0.3746

As for equilibrium

∑ Fy  = 0

2 Tx   = 2 T sin 22⁰  =  P

2T * 0,3746  =  19.6

T = 26.16 [N]

mk./km: lm

step-by-step explanation:

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he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: