The following table shows a portion of a five-year amortization schedule.
5 year amortization schedule
loan amount or principal s 10.900.00
interest rate on loan
10.95%
extra payment to principal s
month payment principal interest balance
15 s 236.72 s 155.87s 80.85 s 8.704.27
16 s 236.72s 157.29 s 79.43s 8.546.98
17 s 236.72s 158.73s 77.99 s 8.388.25
18 s 236.72s 160.18 s 76.54s 8.228.07
19 s 236.72s 161.64s 75.08 s 8.066.43
20 s 236.72s 163.11 s 73.61s 7.903.32
what percent of the payments made were due to interest for the months shown?
a. 30.9%
b. 32.6%
c. 62.5%
d. 63.4%

give more details

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the monthly balance will be $75,000