according to statistics reported on cnbc, a surprising number of motor vehicles are not covered by insurance (cnbc, february 23, 2006). sample results, consistent with the cbnc report, showed 46 out of 200 vehicles were not covered by insurance. develop a 95% confidence interval for the population proportion.

The 95% confidence interval would be given by (0.172;0.288)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

number of vehicles that were not covered by insurance

random sample taken

estimated proportion of vehicles that were not covered by insurance

true population proportion of vehicles that were not covered by insurance

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by and . And the critical value would be given by:

The confidence interval for the mean is given by the following formula:  

If we replace the values obtained we got:

The 95% confidence interval would be given by (0.172;0.288)

d

step-by-step explanation:

i used the pitagoras theoreme

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195