Read the proof.

given: aeec; bddc

prove: △aec ~ △bdc

triangle a e c is shown. line segment b d is drawn near point c to form triangle b d c.

statement reason
1. aeec; bddc 1. given
2. ∠aec is a rt. ∠; ∠bdc is a rt. ∠ 2. definition of perpendicular
3. ∠aec ≅ ∠bdc 3. all right angles are congruent
4. ? 4. reflexive property
5. △aec ~ △bdc 5. aa similarity theorem
what is the missing statement in step 4?

∠ace ≅ ∠bcd
∠eab ≅ ∠dbc
∠eac ≅ ∠eac
∠cbd ≅ ∠dbc