Two cards are randomly selected from an ordinary playing deck.
what is the probability that one of the cards is an ace and the other one is either a ten, a jack, a queen or a king?

The required probability is 0.048

Step-by-step explanation:

Consider the provided information.

Out of 52 card we need to select only 2.

Therefore the sample space is:

One card is Ace. The number of Ace are 4 and we need to select one of them.

This can be written as:

The second card can be Ten or a Jack or a Queen or a King.

There are 4 Ten, 4 jack, 4 Queen, and 4 king in a deck and we need to select only 1 out of them.

So we can say that we need to select 1 card out of 16.

This can be written as:

Thus, the probability that one of the cards is an ace and the other one is either a ten, a jack, a queen or a king is:

Hence, the required probability is 0.048

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)