Refer to the accompanying ti-83/84 plus calculator display of a 95% confidence interval. the sample display results from using a simple random sample of the amounts of tar (in milligrams) in cigarettes that are all king size, nonfiltered, nonmenthol, and non-light. express the confidence interval in the format of x overbarplus or minuse. zinterval (21.182,23.958) x overbarequals22.57 nequals25 the confidence interval is nothingplus or minus nothing.

[22.57 ± 2.776]

Step-by-step explanation:

Hello!

You have the 95% Confidence Z-interval (21.182;23.958), the mean X[bar]= 22.57 and the sample size n=25.

The formula for the Z interval is

[X[bar] ± ]

The value of Z comes from tha standard normal table:

The semiamplitude (d) or margin of error (E) of the interval is:

E or d= (Upperbond- Lowerbond)/2 = (23.958-21.182)/2 = 2.776

[X[bar] ± E]

[22.57 ± 2.776]

I hope it helps!

may i see the picture? it would a lot, xox

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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