Acompany sells widgets. the amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. using this equation, find out what price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit.

y

=

−

2

x

2

+

113

x

−

497

y=−2x

2

+113x−497

28.25

Step-by-step explanation:

Equation is: y = - 2x^2 + 113x - 497

In order to find out maximum of X, first step is to take derrivative of the function y = - 2x^2 + 113x -497.

When we do that, derrivative function is:

dy/dx = - 2 * 2 x + 113 * 1 = - 4x +113

At the maximum point derrvative function equals to zero.

So, - 4x + 113 = 0

-4x = -113

x = 28.25

So, the selling price should be 28.25

The answer is $50.50

Step-by-step explanation:

Find: Price→x-value

When you grapg it you get 50.50 as your x so that is your answer

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)