Solve the following initial value problem: cos(ð¡)2ðyðð¡=1 with y(12)=tan(12). (find y as a function of ð¡.) y= . b. on what interval is the solution valid? (your answer should involve pi.) it is valid for < ð¡< . c. find the limit of the solution as ð¡ approaches the left end of the interval. (your answer should be a number or "pinf" or "minf". "pinf" stands for plus infinity and "minf" stands for minus infinity.)

i need a picture

step-by-step explanation:

where is the option given

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.