The sum of two numbers is 52. one number is 3 times as large as the other number. which is the larger number

The two number are 39 and 13

Solution:

Let the two numbers be "a" and "b"

Let the larger number be "a" and the smaller number be "b"

Given that, sum of two numbers is 52

a + b = 52 eqn 1

One number is 3 times as large as the other number

Larger number = 3 times smaller number

a = 3b eqn 2

Let us solve eqn 1and eqn 2

Substitute eqn 2 in eqn 1

3b + b = 52

4b = 52

b = 13

Substitute b = 13 in eqn 2

a = 3(13)

a = 39

Thus the two number are 39 and 13

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )