Ahonda dealership sells both motorcycles and cars. there are a total of 200 vehicles on the dealerships lot. the detailer cleaned all the wheels which totaled to 698 wheels. how many motorcycles are there on the lot

There are 51 motorcycles in lot

Solution:

Let "x" be the number of motorcycles

Let "y" be the number of cars

There are a total of 200 vehicles on the dealerships lot

Therefore, we frame a equation as,

number of motorcycles + number of cars = 200

x + y = 200 eqn 1

The detailer cleaned all the wheels which totaled to 698 wheels

We know that,

In a car there are 4 wheels and in a motorcycle there are 2 wheels

Thus we get,

2x + 4y = 698 eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

x = 200 - y eqn 3

Substitute eqn 3 in eqn 2

2(200 - y) + 4y = 698

400 - 2y + 4y = 698

400 + 2y = 698

2y = 698 - 400

2y = 298

Substitute y = 149 in eqn 3

x = 200 - 149

Thus there are 51 motorcycles in lot

what is the starting amount? the question is not clear sorry.

step-by-step explanation: