What is the numerator of the simplified sum?
x/x^2 +3x+2 + 3/x+1

Question:

What is the numerator of the simplified sum?

x/x^2 +3x+2 + 3/x+1

Answer & Step-by-step explanation:

The given equation is as follows.

       \frac{x}{x^{2}+3x+2} + \frac{3}{x+1}

Taking L.C.M, the equation will become as follows.

      \frac{x(x+1)+ 3(x^{2}+3x+2)}{(x^{2}+3x+2)(x+1)}   (1)

Factorize the equation x^{2}+3x+2 in the denominator as follows.

        x^{2}+3x+2

      =  x^{2} + 2x + x + 2  

      = x(x+2) + 1(x + 2)  

      = (x+1)(x+2) (2)

Put the factors in equation (2) in to equation (1), then the equation will become as follows.

     \frac{x(x+1)+ 3(x^{2}+3x+2)}{(x^{2}+3x+2)(x+1)}

    = \frac{x^{2}+x +3x^{2}+9x+6)}{(x+1)(x+2)(x+1)}

    = \frac{4x^{2}+10x+6}{(x+1)^{2}(x+2)}

Now, factorize the numerator as follows.

      \frac{4x^{2}+10x+6}{(x+1)^{2}(x+2)}

   = \frac{4x^{2}+4x+6x+6}{(x+1)^{2}(x+2)}

   = \frac{4x(x+1) + 6(x+1)}{(x+1)^{2}(x+2)}

   = \frac{(4x+6)(x+1)}{(x+1)^{2}(x+2)}

Cancelling (x+1) from both numerator and denominator. Then the equation will be written as follows.

      \frac{(4x+6)(x+1)}{(x+1)^{2}(x+2)}

    = \frac{(4x+6)}{(x+1)(x+2)}

The numerator of simplified sum is (4x+6).