There are 18 students involved in the class production of arsenic and old lace. a) in how many ways can the teacher cast the play if there are five male roles and seven female roles and the class has nine male and nine female students? b) in how many ways can the teacher cast the play if jean will play the young female part only if jovane plays the male lead? c) in how many ways can the teacher cast the play if all the roles could be played by either a male or a female student?

a. 9Permutation5 × 9Permutation7

= 2743372800

b. for boys there are 9Combination5 = 126 combos

of which jovane

and in 14 of which 1/5 of 70 he will have the lead

for girls there are 9C7 = 36 combos

in 28 of which 7/9 of 36 jean will figure

there are thus a total of 126×36 combos

and we multiplied them by 5!×7!

to get permutations needed for cases:

- jovane chosen & not given lead & jean chosen : 56×28

- jovane not chosen & jean chosen: 56×28

total such combos = 3136

we have now to multiply by 5!×6×6!

to get permutations with restriction,

For instance(5!×7! - 5!×6×6!) = 86400 less for each such combo

so finally, all we have to do

is to subtract 3136×86400 from ans of qa to give

2743372800 - 270950400

= 2472422400

c. 18Permutation12

= 8892185702400

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours