Lou and jacob each sold 200 pieces of jewelry. if 20% of lou’s sales were rings and jacob sold 35 rings who sold more rings? how many more?

Lou has sold more rings than Jacob

Lou has sold 5 more rings than Jacob

Solution:

Lou and Jacob each sold 200 pieces of jewelry

Therefore,

Lou: 200 pieces sold

Jacob: 200 pieces sold

Also, given that,

20% of lou’s sales were rings and Jacob sold 35 rings

Therefore, we can say,

For Lou : 20 % of 200 were rings

Let us evaluate 20 % of 200

Thus Lou sold 40 rings

Also, given that Jacob sold 35 rings

Thus, Lou has sold more rings than Jacob

Difference = 40 - 35 = 5

Lou has sold 5 more rings than Jacob

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)