Given that h(x)=-(x-1)^2-1h(x)=−(x−1) 2 −1h, (, x, ), equals, minus, (, x, minus, 1, ), squared, minus, 1, write an expression for f(x)f(x)f, (, x, )in terms of xxx.

22 dimes and 9 nickels

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

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