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Mathematics, 21.01.2020 18:31, berniceallonce22
A(t)=(t-k)(t-3)(t-6)(t+3)a(t)=(t−k) (t−3)(t−6)(t+3)a, left parenthesis, t, right parenthesis, equals, left parenthesis, t, minus, k, right parenthesis, left parenthesis, t, minus, 3, right parenthesis, left parenthesis, t, minus, 6, right parenthesis, left parenthesis, t, plus, 3, right parenthesis is a polynomial function of ttt, where kkk is a constant. given that a(2)=0a(2)=0a, left parenthesis, 2, right parenthesis, equals, 0, what is the absolute value of the product of the zeros of aaa?
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Answers: 3
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A(t)=(t-k)(t-3)(t-6)(t+3)a(t)=(t−k) (t−3)(t−6)(t+3)a, left parenthesis, t, right parenthesis, equals...
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