Two adjacent sides of a parallelogram have lengths a and b and the angle between these two sides is theta. express the area of the parallelogram in terms of a, b, and theta

A = a*b*Cos(θ-90º)

Step-by-step explanation:

Area of a parallelogram : A = b*h, where h is the height

h form 90º angle with b.

h = a*Cos (θ-90º) in a sub-triangle formed by h, a and a*Sin(θ-90º)

In the Pythagoearn identity for this sub-triangle:

(a*Sin(θ-90º))² + (a*Cos(θ-90º))² = a²

(a*Sin(θ-90º))² + h² = a²

h² = a² (1 - Sin² (θ-90ª))

h² = a² (Cos²(θ-90º)

h = a (Cos (θ-90º))

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)