If an insurance company has 1 policies, and each has 0.1 probability of making a claim, what is the standard deviation of the fraction of policies which result in a claim?

0.003

Step-by-step explanation:

Since each of the policy have the same chance of success, then it follows a binomial distribution (only two outcome; success or failure).

α = √(p(1-p)/n) = √ (0.1 ( 1-0.1)/ 10000) = √ 0.000009 = 0.003

where p = 0.1, α = standard deviation.

S.D = +/- 0.003

The standard deviation of the fraction of policies which result in a claim is +/- 0.003

Step-by-step explanation:

Given;

Probability of making a claim p = 0.1

Number of company policies n = 10000

Standard deviation is the measure of how spread out numbers are.

S.D = √(p(1-p)/n)

Where,

p = 0.1

n = 10000

S.D = √(0.1(1-0.1)/10000)

S.D = √(0.1×0.9/10000)

S.D = √(0.000009)

S.D = +/- 0.003

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

which expression can be used to convert 80 us dollars (usd) to australian dollars (aud)?

1 usd = 1.0343 aud

1 aud = 0.9668 usd

step-by-step explanation:

sorry just need the points