If you toss four fair coins, in how many ways can you obtain at least one head? group of answer choicesa. 1/16b. 1/2c. 3/16d. 11/16e. 3/8

The correct answer is:

15/16

Step-by-step explanation:

In a toss of four fair coin, there are possibility of 16 occurrence because a coin have an head and a tail (2).

In 4 coins, we will have : 2⁴ = 16

Let S be the sample space, then:

S = { , HHHT, HHTT, HTTT, TTTH, TTHH, TTTH, , HTHT, THTH, HHTH, HTHH, TTHT,THHT, HTTH, THTT}

Let E₁ be the event that at least one head appears:

n(E₁) = 15

∴ Pr (E₁) = n(E₁)/ n(S)

             = 15/16

answer: can you give the

step-by-step explanation:

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6