An apple costs the same as 2 oranges. together, an orange and a banana cost 10 cent more than an apple. two oranges cost 15 cent more than a banana. what is the cost for one of each fruit

The cost of 1 apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents

Solution:

Let "a" be the cost of 1 apple

Let "b" be the cost of 1 banana

Let "r" be the cost of 1 orange

Given that Apple costs the same as 2 oranges

cost of 1 apple = 2 (cost of 1 orange)

a = 2r eqn 1

Together, an orange and a banana cost 10 cents more than an apple

cost of 1 orange + cost of 1 banana = 10 + cost of 1 apple

r + b = 10 + a eqn 2

Two oranges cost 15 cents more that a banana

cost of 2 orange = 15 + cost of 1 banana

2r = 15 + b eqn 3

Let us solve eqn 1, eqn 2 and eqn 3

From eqn 1 and eqn 3, substitute eqn 1 in eqn 3

a = b + 15 --- eqn 4

Substitute eqn 4 in eqn 2

r + b = 10 + b + 15

r = 10 + 15

Substitute r = 25 in eqn 3

2(25) = 15 + b

50 - 15 = b

Substitute b = 35 in eqn 4

a = 35 + 15

Thus cost of one apple is 50 cents and cost of 1 banana is 35 cents and cost of 1 orange is 25 cents

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2