Mis the midpoint of segment vw. vm is 4x-1 and mw is 3x+3. find the value of x.

The value of x = -7/2

Since M is the midpoint of VW and VM = 4x - 1 and MW = 3x + 3, it implies that

MW = VM/2

So, 3x + 3 = (4x - 1)/2

cross-multiplying, we have

2(3x + 3) = 4x - 1

Expanding the bracket, we have

6x + 6 = 4x - 1

Subtracting 4x from both sides, we have

6x - 4x + 6 = 4x - 4x - 1

2x + 6 = - 1

Subtracting 6 from both sides, we have

2x + 6 - 6 = -1 - 6

2x = -7

Dividing through by 2, we have

x = -7/2

So, the value of x = -7/2

Learn more about midpoint of a segment here:

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x=4

Step-by-step explanation:

Because M is the midpoint of VW both segments VM and MW are created as EQUALS because VW is cut in half to make these segments. Since the length of VM and MW are equal then you can use the equation 4x-1=3x+3. First add one on both sides which will give you the equation 4x=3x+4. Lastly you want to isolate x by subtracting 3x on both sides to then get x=4

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

594 square inches

step-by-step explanation:

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