water flows through a pipe of diameter 4cms with a velocity of
0.5m/s into a tank with a diameter of 1.5m. what will be the
height of water in the tank after 1 hour?

  1.28 m

Step-by-step explanation:

The speed at which water rises in the tank is proportional to the speed of the water in the pipe and inversely proportional to the ratio of the tank area to the pipe area.

The ratio of tank area to pipe area is the square of the ratio of their diameters:

  ((150 cm)/(4 cm))² = 1406.25

Then the rate of rise of water in the tank is ...

  (0.5 m/s)/(1406.25)

After 1 hour = 3600 seconds, the height of the water will be ...

  rise = (time)(rate of rise)

  (3600 s)(0.5 m/s)/1406.25 = 1.28 m

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

27 +27 or 27times 2=54

the diffrence is 0