Let (3,-2) be a point on the terminal side of theta in standard position. find exact values of the six trigonometric functions of theta

Step-by-step explanation:

The distance of the point from the origin is ...

  r = √(3² +(-2)²) = √13

We know that ...

  x = r·cos(θ)   ⇒   cos(θ) = x/r = 3/√13 = (3√13)/13

  y = r·sin(θ)   ⇒   sin(θ) = y/r = -2/√13 = (-2√13)/13

  tan(θ) = sin(θ)/cos(θ) = -2/3

  sec(θ) = 1/cos(θ) = (√13)/3

  csc(θ) = 1/sin(θ) = (-√13)/2

  cot(θ) = 1/tan(θ) = -3/2

c.

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116