How do you figure out coordinates of a line if you only have the equation?

Step-by-step explanation:

u can figure the x and y intercepts by just the equation. U can also figure points by subbing.

example :

6x + 2y = 12there are 2 ways to find the y interceptu can either sub in 0 for x and solve for yor u can put the equation in y = mx + b form where b is ur y int.

y = mx + b form :

6x + 2y = 12

2y = -6x + 12

y = (-6/2)x + 12/2

y = -3x + 6so the y int is 6 or (0,6)

or u can sub in 0 for x and solve for y

6x + 2y = 12

6(0) + 2y = 12

2y = 12

y = 12/2

y = 6y int is 6or (0,6)

to find the x intercept. sub in 0 for y and solve for x

6x + 2y = 12

6x + 2(0) = 12

6x + 0 = 12

6x = 12

x = 12/6

x = 2so ur x intercept is 2 or (2,0)

if u dont have a graph to look at to plot points using the slope, then u can easily sub in any number for x and find y to find points on ur line.

6x + 2y = 12pick any number for x...besides 0x = 1

6(1) + 2y = 12

6 + 2y = 12

2y = -6 + 12

2y = 6

y = 6/2

y = 3so one point on this line is : (1,3)

6x + 2y = 12when x = 2

6(2) + 2y = 12

12 + 2y = 12

2y = 12 - 12

2y = 0

y = 0and another point is (2,0)

u can keep subbing in any number for x to find ythis will find points on ur line.

correct answer:

b.(19,-2)