Find the values of m and n so that the polynomial p(z)=z^3-mz^2-13z+n has (z-1) and (z+3) as factors
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pls answee fast i have exam tomo

m = 3, n = 15.

Step-by-step explanation:

As the factors are z-1 and z+3 then z = 1 and z = -3 are zeroes of the function so substituting for z = 1 and z = -3:

1^3 - 1m - 13(1) + n = 0

n - m = 12 (a)

(-3)^3 - 9m + 39 + n = 0

n - 9m = -12 (b).

Subtract:  (a) - (b):

8m = 24

m = 3.

Substituting m = 3 in equation (a):

n - 3 = 12

n = 15.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".